Question Number 77716 by aliesam last updated on 09/Jan/20

Commented by MJS last updated on 09/Jan/20

Commented by aliesam last updated on 09/Jan/20

Answered by MJS last updated on 09/Jan/20
![∫sin x^4 dx=−(i/2)∫(e^(ix^4 ) −e^(−ix^4 ) )dx= [t=x((−i))^(1/4) =(x/2)((√(2+(√2)))−i(√(2−(√2)))) → dx=(dt/2)((√(2+(√2)))+i(√(2−(√2))))] =(1/4)((√(2−(√2)))−i(√(2+(√2))))∫(e^(−t^4 ) +e^t^4 )dt ∫e^(−t^4 ) dt=−((√2)/8)(1−i)Γ ((1/4), −t^4 ) ∫e^t^4 dt=−(1/4)Γ ((1/4), t^4 ) ...](https://www.tinkutara.com/question/Q77748.png)
Commented by aliesam last updated on 09/Jan/20
