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sinh-ln-x-1-x-2-A-2x-B-1-x-C-x-2-D-x-




Question Number 71235 by Rio Michael last updated on 13/Oct/19
sinh[ln (x + (√(1 + x^2 ))) ] ≡     A.  2x  B.  (1/x)  C.  x^2   D.  x
sinh[ln(x+1+x2)]A.2xB.1xC.x2D.x
Commented by mathmax by abdo last updated on 13/Oct/19
sh{ln(x+(√(1+x^2 )))} =((e^(ln(x+(√(1+x^2 )))) −e^(−ln(x+(√(1+x^2 )))) )/2)  =((x+(√(1+x^2 ))−(1/(x+(√(1+x^2 )))))/2) =(((x+(√(1+x^2 )))^2 −1)/(2(x+(√(1+x^2 )))))  =((x^2 +2x(√(1+x^2 ))  +1+x^2 −1)/(2(x+(√(1+x^2 ))))) =((2x^2  +2x(√(1+x^2 )))/(2(x+(√(1+x^2 )))))  =((x(x+(√(1+x^2 )))/(x+(√(1+x^2 )))) =x  also we can use that ln(x+(√(1+x^2 )))=argsh(x)=sh^(−1) (x)
sh{ln(x+1+x2)}=eln(x+1+x2)eln(x+1+x2)2=x+1+x21x+1+x22=(x+1+x2)212(x+1+x2)=x2+2x1+x2+1+x212(x+1+x2)=2x2+2x1+x22(x+1+x2)=x(x+1+x2x+1+x2=xalsowecanusethatln(x+1+x2)=argsh(x)=sh1(x)
Answered by MJS last updated on 13/Oct/19
sinh α =(1/2)(e^α −e^(−α) )  ⇒ answer is D. x
sinhα=12(eαeα)answerisD.x
Commented by Rio Michael last updated on 13/Oct/19
i don′t understand the working sir
idontunderstandtheworkingsir
Commented by MJS last updated on 13/Oct/19
first, sorry I made a typo in the formula    sinh ln (x+(√(x^2 +1))) =(1/2)(x+(√(x^2 +1))−(1/(x+(√(x^2 +1)))))=  =(1/2)×(((x+(√(x^2 +1)))^2 −1)/(x+(√(x^2 +1))))=(1/2)×((2x^2 +2x(√(x^2 +1)))/(x+(√(x^2 +1))))=x
first,sorryImadeatypointheformulasinhln(x+x2+1)=12(x+x2+11x+x2+1)==12×(x+x2+1)21x+x2+1=12×2x2+2xx2+1x+x2+1=x
Commented by Rio Michael last updated on 13/Oct/19
thanks sir
thankssir
Answered by mr W last updated on 13/Oct/19
let t=ln (x+(√(1+x^2 )))  e^t =x+(√(1+x^2 ))   ...(i)  e^(−t) =(1/(x+(√(1+x^2 ))))=−x+(√(1+x^2 ))  −e^(−t) =x−(√(1+x^2 ))   ...(ii)  e^t −e^(−t) =2x  ((e^t −e^(−t) )/2)=x  ⇒sinh t=x  i.e. sinh [ln (x+(√(1+x^2 )))]=x  ⇒answer D
lett=ln(x+1+x2)et=x+1+x2(i)et=1x+1+x2=x+1+x2et=x1+x2(ii)etet=2xetet2=xsinht=xi.e.sinh[ln(x+1+x2)]=xanswerD
Commented by Rio Michael last updated on 13/Oct/19
thanks sirs
thankssirs

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