Solve-3cos5x-4sin4x-3-0-in-R- Tinku Tara June 3, 2023 Trigonometry 0 Comments FacebookTweetPin Question Number 137103 by Boucatchou last updated on 29/Mar/21 Solve3cos5x−4sin4x−3=0inR Answered by MJS_new last updated on 30/Mar/21 obviouslyx=2nπisasolutiontheotherscanonlybeapproximatedx≈.966119+2nπx≈1.47065+2nπx≈2.39052+2nπx≈2.86574+2nπx≈5.90132+2nπwithn∈Z Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Can-you-please-show-me-how-to-solve-L-lim-n-x-n-n-Next Next post: Question-137106 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.