solve-5-3x-2-8-4x-2-33-9x-8-

Question Number 8350 by Nayon last updated on 09/Oct/16

s o l v e :

\frac{5}{3 x + 2} + \frac{8}{4 x + 2} = \frac{33}{9 x + 8}

Answered by Rasheed Soomro last updated on 10/Oct/16

\frac{5}{3 x + 2} + \frac{8}{4 x + 2} = \frac{33}{9 x + 8}

Multiplying both sides by (3 x + 2) (4 x + 2) (9 x + 8)

5 (4 x + 2) (9 x + 8) + 8 (3 x + 2) (9 x + 8) = 33 (3 x + 2) (4 x + 2)

5 ({36 x}^{2} + 50 x + 16) + 8 ({27 x}^{2} + 42 x + 16)

= 33 ({12 x}^{2} + 14 x + 4)

{180 x}^{2} + 250 x + 80 + {216 x}^{2} + 336 x + 128 - {396 x}^{2} - 462 x - 132 = 0

124 x + 76 = 0

x = - \frac{76}{124} = \frac{19}{31}