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Question Number 10836 by okhema last updated on 27/Feb/17
solve cos2θ−3cosθ=1  for o≤θ≤2π
solvecos2θ3cosθ=1foroθ2π
Answered by ridwan balatif last updated on 27/Feb/17
cos2θ−3cosθ=1  (2cos^2 θ−1)−3cosθ=1  2cos^2 θ−3cosθ−2=0  (2cosθ+1)(cosθ−2)=0  cosθ=−1/2 ∨ cosθ=2(IMPOSSIBLE)    cosθ=−1/2  θ=(2/3)π,(4/3)π
cos2θ3cosθ=1(2cos2θ1)3cosθ=12cos2θ3cosθ2=0(2cosθ+1)(cosθ2)=0cosθ=1/2cosθ=2(IMPOSSIBLE)cosθ=1/2θ=23π,43π

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