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Solve-for-real-numbers-4sin-pi-26-4xsin-3pi-26-4sin-9pi-26-x-13-




Question Number 140193 by mathdanisur last updated on 05/May/21
Solve for real numbers  4sin(π/(26)) + 4xsin((3π)/(26)) + 4sin((9π)/(26)) = x+(√(13))
Solveforrealnumbers4sinπ26+4xsin3π26+4sin9π26=x+13
Answered by Dwaipayan Shikari last updated on 05/May/21
x(1−4sin((3π)/(26)))=4(sin((9π)/(26))+sin(π/(26)))−(√(13))  x=((4(sin((9π)/(26))+sin(π/(16)))−(√(13)))/((1−4sin((3π)/(26)))))
x(14sin3π26)=4(sin9π26+sinπ26)13x=4(sin9π26+sinπ16)13(14sin3π26)
Commented by mathdanisur last updated on 05/May/21
continued Sir pliz
continuedSirpliz

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