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Question Number 8886 by vuckintv last updated on 04/Nov/16
solve for β  T(h)=T_s −((√π)/2)×(β/ξ)×[erf(ξH)−erf(ξh)]
solveforβT(h)=Tsπ2×βξ×[erf(ξH)erf(ξh)]
Answered by Rasheed Soomro last updated on 04/Nov/16
T(h)=T_s −((√π)/2)×(β/ξ)×[erf(ξH)−erf(ξh)]  ((√π)/2)×(β/ξ)×[erf(ξH)−erf(ξh)]=T_s −T(h)  (β/ξ)=((2(T_s −T(h)))/( (√π)([erf(ξH)−erf(ξh)])))  β=((2ξ(T_s −T(h)))/( (√π)([erf(ξH)−erf(ξh)])))
T(h)=Tsπ2×βξ×[erf(ξH)erf(ξh)]π2×βξ×[erf(ξH)erf(ξh)]=TsT(h)βξ=2(TsT(h))π([erf(ξH)erf(ξh)])β=2ξ(TsT(h))π([erf(ξH)erf(ξh)])

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