Menu Close

solve-for-x-in-terms-of-a-R-x-x-x-2-a-x-a-2-a-2-




Question Number 73131 by behi83417@gmail.com last updated on 06/Nov/19
solve for x,in terms of:  a∈R .     x+(√x)+(√(x^2 −a))+(√(x−a^2 ))=a^2
solveforx,intermsof:aR.x+x+x2a+xa2=a2
Commented by mr W last updated on 06/Nov/19
x≥0  x−a^2 ≥0  x^2 −a≥0  (x−a^2 )+(√x)+(√(x^2 −a))+(√(x−a^2 ))≥0  ⇒only solution is, when  x−a^2 =0  x=0  x^2 −a=0  ⇒a=0 and x=0  if a≠0, there is no solution.
x0xa20x2a0(xa2)+x+x2a+xa20onlysolutionis,whenxa2=0x=0x2a=0a=0andx=0ifa0,thereisnosolution.
Commented by behi83417@gmail.com last updated on 06/Nov/19
thanks  in advance dear master.
thanksinadvancedearmaster.

Leave a Reply

Your email address will not be published. Required fields are marked *