solve-for-z-C-z-a-bi-z-a-bi-r-R-r-2-z-2-z-r-2-z-2-z-

Question Number 76397 by MJS last updated on 27/Dec/19

solve for z \in C

[z = a + b i; \bar{z} = a - b i; r \in R]

\sqrt{r^{2} - z^{2}} = \bar{z}

\sqrt{r^{2} + z^{2}} = \bar{z}

Commented by mr W last updated on 27/Dec/19

i s t h e r e a s o l u t i o n o t h e r t h a n

z = 0 a n d r = 0 ?

Commented by MJS last updated on 27/Dec/19

I found no other solution for the 2^{nd} one

\sqrt{r^{2} - z^{2}} = \bar{z} \Rightarrow z = \frac{\sqrt{2 (r^{2} + 2 s^{2})}}{2} + s i with r, s \in R

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