solve-in-Z-1-x-1-y-1-p-with-p-P-

Question Number 71294 by Mohamed Amine Bouguezzoul last updated on 13/Oct/19

s o l v e i n Z \frac{1}{x} + \frac{1}{y} = \frac{1}{p} w i t h p \in P

Commented by Rasheed.Sindhi last updated on 13/Oct/19

\frac{x + y}{x y} = \frac{1}{p}

\frac{x y}{x + y} = p

x y = (x + y) p

T h e d i f f e r e n c e b e t w e e n t h i s q u e s t i o n

You can't use 'macro parameter character #' in math mode

i n s t e a d o f p \in P . I - e t h i s q u e s t i o n i s

You can't use 'macro parameter character #' in math mode

Answered by mr W last updated on 13/Oct/19

x = 1 + p

y = (1 + p) p

e x a m p l e s :

\frac{1}{3} + \frac{1}{6} = \frac{1}{2}

\frac{1}{4} + \frac{1}{12} = \frac{1}{3}

\frac{1}{6} + \frac{1}{30} = \frac{1}{5}

\dots \dots

Commented by Mohamed Amine Bouguezzoul last updated on 13/Oct/19

n i c e w o r k b u t t h e r e e x i s t m o r e s o l u t i o n s

f o r e x a m p l e \frac{1}{10} + \frac{1}{10} = \frac{1}{5}

Commented by mr W last updated on 13/Oct/19

{t h a t}^{'} s t r u e s i r . p l e a s e s e e Q 69939

f o r m o r e .

Commented by Mohamed Amine Bouguezzoul last updated on 13/Oct/19

g o d b l e s s y o u s i r