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Question Number 73033 by mathmax by abdo last updated on 05/Nov/19
solve inside N^2     x(x+1)=4y(y+1)
solveinsideN2x(x+1)=4y(y+1)
Answered by mind is power last updated on 05/Nov/19
⇔4x(x+1)=16y(y+1)  ⇒x≥y≥0  ⇔(2x+1)^2 −1=(4y+2)^2 −4  ⇒(4y+2)^2 −(2x+1)^2 =3  ⇒(4y−2x+1)(4y+2x+3)=3  ⇒ { (( 4y−2x+1=1)),((4y+2x+3=3)) :}  ⇒x=y=0
4x(x+1)=16y(y+1)xy0(2x+1)21=(4y+2)24(4y+2)2(2x+1)2=3(4y2x+1)(4y+2x+3)=3{4y2x+1=14y+2x+3=3x=y=0

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