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Solve-sin-2x-2sin-2-x-3-cos-x-for-x-real-and-0-x-2pi-




Question Number 136268 by EDWIN88 last updated on 20/Mar/21
Solve sin (2x)−2sin^2 (x)=(√3) cos x for   x real and 0≤x≤2π
Solvesin(2x)2sin2(x)=3cosxforxrealand0x2π

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