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solve-sin-2x-y-3-cosx-y-xe-x-




Question Number 69789 by mathmax by abdo last updated on 27/Sep/19
solve sin(2x)y^′  −3(cosx)y =xe^(−x)
$${solve}\:{sin}\left(\mathrm{2}{x}\right){y}^{'} \:−\mathrm{3}\left({cosx}\right){y}\:={xe}^{−{x}} \\ $$

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