Solve-the-equation-p-tan-1-2x-tan-1-3x-pi-4-

Question Number 12532 by tawa last updated on 24/Apr/17

Solve the equation : p

\tan^{- 1} (2 x) + \tan^{- 1} (3 x) = \frac{π}{4}

Answered by mrW1 last updated on 25/Apr/17

\tan [\tan^{- 1} (2 x) + \tan^{- 1} (3 x)] = \tan (\frac{π}{4})

\frac{2 x + 3 x}{1 - 2 x \times 3 x} = 1

5 x = 1 - 6 x^{2}

6 x^{2} + 5 x - 1 = 0

(6 x - 1) (x + 1) = 0

x = \frac{1}{6}

x = - 1 (n o s o l u t i o n, s i n c e x > 0)

Commented by tawa last updated on 25/Apr/17

God bless you sir

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