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Solve-the-following-DE-y-dy-dx-6x-5y-0-x-0-y-0-




Question Number 1352 by 112358 last updated on 24/Jul/15
Solve the following DE :  y(dy/dx)+6x+5y=0     (x≠0,y≠0)
$${Solve}\:{the}\:{following}\:{DE}\:: \\ $$$${y}\frac{{dy}}{{dx}}+\mathrm{6}{x}+\mathrm{5}{y}=\mathrm{0}\:\:\:\:\:\left({x}\neq\mathrm{0},{y}\neq\mathrm{0}\right) \\ $$
Answered by imhunter last updated on 27/Jul/15
q.no.1352           y dy/dx=−6x−5y        ydy/−5y=−6xdx  on integrating both sides  y=3x^(2 ) +c
$${q}.{no}.\mathrm{1352}\:\:\:\:\:\:\:\:\:\:\:{y}\:{dy}/{dx}=−\mathrm{6}{x}−\mathrm{5}{y} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$${ydy}/−\mathrm{5}{y}=−\mathrm{6}{xdx} \\ $$$${on}\:{integrating}\:{both}\:{sides} \\ $$$${y}=\mathrm{3}{x}^{\mathrm{2}\:} +{c} \\ $$

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