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Solve-the-partial-fraction-4s-3-39-2-s-2-42s-40-s-s-2-s-2-6s-10-




Question Number 6861 by Tawakalitu. last updated on 31/Jul/16
Solve the partial fraction   ((4s^3  − ((39)/2)s^2  + 42s − 40)/(s(s − 2)(s^2  − 6s + 10)))
$${Solve}\:{the}\:{partial}\:{fraction}\: \\ $$$$\frac{\mathrm{4}{s}^{\mathrm{3}} \:−\:\frac{\mathrm{39}}{\mathrm{2}}{s}^{\mathrm{2}} \:+\:\mathrm{42}{s}\:−\:\mathrm{40}}{{s}\left({s}\:−\:\mathrm{2}\right)\left({s}^{\mathrm{2}} \:−\:\mathrm{6}{s}\:+\:\mathrm{10}\right)} \\ $$

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