Solve-using-trig-method-8x-3-4x-2-4x-1-0- Tinku Tara June 3, 2023 Algebra FacebookTweetPin Question Number 131421 by Lordose last updated on 04/Feb/21 Solveusingtrigmethod8x3−4x2−4x+1=0 Commented by Dwaipayan Shikari last updated on 04/Feb/21 x=y+168y3+127+4y2+2y3−4y2−4y3−19−4y−23+1=0⇒8y3−14y3+727=0y=Rcosθ⇒cos3θ−712R2cosθ+7216R3=027647Comparingwithcos3θ−34cosθ−14cos3θ=0712R2=34⇒R=±73cos3θ=±27647θ=kπ+13cos−1±(27647)⇒Rcosθ=±73cos(kπ+13cos−1(±27647))x=±73cos(kπ+13cos−1(±27647))−16 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: a-n-1-2-3-4-5-n-n-1-mod-2-a-n-1-2-3-4-5-6-n-n-0-mod-2-lim-n-a-n-1-Next Next post: Q-Define-LHD-left-hand-derivative-f-a-0-lim-h-0-f-a-h-f-a-h-