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solve-x-2-y-xy-3y-4e-x-

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Question Number 66005 by mathmax by abdo last updated on 07/Aug/19
solve x^2 y^(′′) +xy^′ −3y =4e^(−x)
$${solve}\:\:\:{x}^{\mathrm{2}} {y}^{''} \:+{xy}^{'} −\mathrm{3}{y}\:=\mathrm{4}{e}^{−{x}} \\ $$

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