solve-x-3-2-x-5- Tinku Tara June 3, 2023 Algebra 0 Comments FacebookTweetPin Question Number 134005 by mr W last updated on 26/Feb/21 solvex3−2⌊x⌋=5 Answered by MJS_new last updated on 26/Feb/21 x=i[ntegerpart]+f[ractalpart](i+f)3−2i=5f=−i+2i+530⩽−i+2i+53⩽1⇒i=1∨i=2⇒f=−1+73∨f=−2+93⇒x=73∨x=93 Commented by mr W last updated on 26/Feb/21 great!thanks! Commented by MJS_new last updated on 26/Feb/21 I′mnotsureif⌊z⌋and⌈z⌉aredefinedforz∈C,maybe⌊a×bi⌋=⌊a⌋+⌊b⌋i?anywayIhaven′ttriedtosolveitforx∉R Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: find-the-value-of-0-arctan-2x-2-x-2-4-dx-Next Next post: sin-72-sin-42-p-tan-12- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![x=i[nteger part]+f[ractal part] (i+f)^3 −2i=5 f=−i+((2i+5))^(1/3) 0≤−i+((2i+5))^(1/3) ≤1 ⇒ i=1∨i=2 ⇒ f=−1+(7)^(1/3) ∨f=−2+(9)^(1/3) ⇒ x=(7)^(1/3) ∨x=(9)^(1/3)](https://www.tinkutara.com/question/Q134027.png)
