Question Number 880 by arnav last updated on 11/Apr/15
$${Solve} \\ $$$$\frac{{x}+\mathrm{3}}{{x}−\mathrm{3}}<\mathrm{1} \\ $$
Answered by 123456 last updated on 11/Apr/15
$$\frac{{x}+\mathrm{3}}{{x}−\mathrm{3}}−\mathrm{1}<\mathrm{0} \\ $$$$\frac{{x}+\mathrm{3}−{x}+\mathrm{3}}{{x}−\mathrm{3}}<\mathrm{0} \\ $$$$\frac{\mathrm{6}}{{x}−\mathrm{3}}<\mathrm{0} \\ $$$${x}−\mathrm{3}<\mathrm{0} \\ $$$${x}<\mathrm{3} \\ $$