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solve-x-6-2x-4-3-3x-2-x-8-




Question Number 5902 by Ashis last updated on 04/Jun/16
solve x  6^(2x+4)   =3^(3x)  2^(x+8)
solvex62x+4=33x2x+8
Commented by prakash jain last updated on 04/Jun/16
6^(2x) 6^4 =3^(3x) 2^x 2^8   (2∙3)^(2x) 3^4 2^4 =3^(3x) 2^x 2^8   2^(2x) 3^(2x) 3^4 2^4 =3^(3x) 2^x 2^8   ((2^(2x) 3^(2x) )/(3^(3x) 2^x ))=(2^8 /(3^4 2^4 ))  (2^x /3^x )=(2^4 /3^4 )  ((2/3))^x =((2/3))^4   x=4
62x64=33x2x28(23)2x3424=33x2x2822x32x3424=33x2x2822x32x33x2x=2834242x3x=2434(23)x=(23)4x=4
Answered by sanusihammed last updated on 04/Jun/16
Solution    6^(2x + 4)  = 3^(3x) 2^(x+8)   Take the logarithm of both sides  log6^(2x+4)  = log(3^(3x) 2^(x+8) )  (2x+4)log6 = log3^(3x)  + log2^(x+8)   (2x+4)log6 = 3xlog3 + (x+8)log2  (2x+4)0.7782 = 3x(0.4771) + (x+8)(0.3010)  1.5564x + 3.1128 = 1.4313x + 0.3010x + 2.408  1.5564x + 3.1128 = 1.7323x + 2.408  collect the like terms  1.7323x−1.5564x = 3.1128−2.408  0.1759x = 0.7048  x = ((0.7048)/(0.1759))  x = 4.0068  Approximately  x = 4
Solution62x+4=33x2x+8Takethelogarithmofbothsideslog62x+4=log(33x2x+8)(2x+4)log6=log33x+log2x+8(2x+4)log6=3xlog3+(x+8)log2(2x+4)0.7782=3x(0.4771)+(x+8)(0.3010)1.5564x+3.1128=1.4313x+0.3010x+2.4081.5564x+3.1128=1.7323x+2.408collecttheliketerms1.7323x1.5564x=3.11282.4080.1759x=0.7048x=0.70480.1759x=4.0068Approximatelyx=4

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