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Suppose-z-50-z-25-m-0-where-z-1-i-2-find-the-value-of-m-




Question Number 143194 by ZiYangLee last updated on 11/Jun/21
Suppose z^(50) +z^(25) +m=0, where z=((1+i)/( (√2)))  find the value of m.
Supposez50+z25+m=0,wherez=1+i2findthevalueofm.
Answered by Olaf_Thorendsen last updated on 11/Jun/21
z = ((1+i)/( (√2))) = e^(i(π/4))   z^(50)  = e^(i(π/4)×50)  = e^(i((25π)/2))  = e^(i(π/2))  = i  z^(25)  = e^(i(π/4)×25)  = e^(i((25π)/4))  = e^(i(π/4))  = ((1+i)/( (√2))) = z  m = −z^(25) −z^(50)  = −(z+i) = −((1+(1+(√2))i)/( (√2)))
z=1+i2=eiπ4z50=eiπ4×50=ei25π2=eiπ2=iz25=eiπ4×25=ei25π4=eiπ4=1+i2=zm=z25z50=(z+i)=1+(1+2)i2
Commented by ZiYangLee last updated on 11/Jun/21
thanks sir
thankssir

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