t-3-t-1-2-t-2-t-1-2-dt-

Question Number 7465 by Yozzia last updated on 30/Aug/16

\int \frac{t^{3}}{{(t - 1)}^{2} {(t^{2} + t + 1)}^{2}} d t = ?

Commented by prakash jain last updated on 30/Aug/16

= \int \frac{t^{3}}{{(t^{3} - 1)}^{2}} d t

= \int \frac{1}{t^{3} - 1} d t + \int \frac{1}{{(t^{3} - 1)}^{2}} d t

w i l l c o n t i n u e s o o n