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tan-2-1-tan-2-2-tan-2-3-tan-2-89-15931-3-




Question Number 140500 by qaz last updated on 08/May/21
tan^2 1°+tan^2 2°+tan^2 3°+...+tan^2 89°=((15931)/3)     ???
$$\mathrm{tan}\:^{\mathrm{2}} \mathrm{1}°+\mathrm{tan}\:^{\mathrm{2}} \mathrm{2}°+\mathrm{tan}\:^{\mathrm{2}} \mathrm{3}°+…+\mathrm{tan}\:^{\mathrm{2}} \mathrm{89}°=\frac{\mathrm{15931}}{\mathrm{3}}\:\:\:\:\:??? \\ $$

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