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tanx-dx-




Question Number 6220 by sanusihammed last updated on 18/Jun/16
∫(√(tanx))  dx
tanxdx
Answered by malwaan last updated on 19/Jun/16
∫(√(tanx)) dx=(1/(2(√2)))(2tan^(−1) (1+(√(2tanx)))  −2tan^(−1) (1−(√(2tanx)))  +log((√(2tanx))−tanx−1)  −log((√(2tanx))+tanx+1))
tanxdx=122(2tan1(1+2tanx)2tan1(12tanx)+log(2tanxtanx1)log(2tanx+tanx+1))
Answered by prakash jain last updated on 20/Jun/16
Please see answer to Question 119.
PleaseseeanswertoQuestion119.

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