Ten-men-are-present-at-a-club-In-how-many-ways-can-four-be-chosen-to-play-bridge-if-two-men-refuse-to-sit-at-the-same-table-

Question Number 11855 by tawa last updated on 02/Apr/17

Ten men are present at a club . In how many ways can four be chosen to

play bridge if two men refuse to sit at the same table .

Answered by sandy_suhendra last updated on 03/Apr/17

let the 2 men are A and B

if A is chosen and B {isn}^{'} t = 8 C 3

if B is chosen and A {isn}^{'} t = 8 C 3

if A and B {aren}^{'} t chosen = 8 C 4

the whole ways = 8 C 3 + 8 C 3 + 8 C 4

= 56 + 56 + 70 = 182

Commented by tawa last updated on 03/Apr/17

God bless you sir .

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