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Question Number 5556 by Rasheed Soomro last updated on 20/May/16
The area of a circle is diretly   proportional to the square of  its diameter.  What is the constant of proportionality?
$$\mathrm{The}\:\mathrm{area}\:\mathrm{of}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{is}\:\mathrm{diretly}\: \\ $$$$\mathrm{proportional}\:\mathrm{to}\:\mathrm{the}\:\mathrm{square}\:\mathrm{of} \\ $$$$\mathrm{its}\:\mathrm{diameter}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{constant}\:\mathrm{of}\:\mathrm{proportionality}? \\ $$
Commented by Yozzii last updated on 20/May/16
A∝d^2   A=k(2r)^2    (d=2r>0)  πr^2 =4kr^2   ⇒k=(π/4) .  Alternatively, since A=(π/4)d^2   ⇒A∝d^2 ⇒k=π/4
$${A}\propto{d}^{\mathrm{2}} \\ $$$${A}={k}\left(\mathrm{2}{r}\right)^{\mathrm{2}} \:\:\:\left({d}=\mathrm{2}{r}>\mathrm{0}\right) \\ $$$$\pi{r}^{\mathrm{2}} =\mathrm{4}{kr}^{\mathrm{2}} \\ $$$$\Rightarrow{k}=\frac{\pi}{\mathrm{4}}\:. \\ $$$${Alternatively},\:{since}\:{A}=\frac{\pi}{\mathrm{4}}{d}^{\mathrm{2}} \\ $$$$\Rightarrow{A}\propto{d}^{\mathrm{2}} \Rightarrow{k}=\pi/\mathrm{4} \\ $$
Commented by Rasheed Soomro last updated on 20/May/16
Your way is better than the way  I saw in a book!
$$\mathrm{Your}\:\mathrm{way}\:\mathrm{is}\:\mathrm{better}\:\mathrm{than}\:\mathrm{the}\:\mathrm{way} \\ $$$$\mathrm{I}\:\mathrm{saw}\:\mathrm{in}\:\mathrm{a}\:\mathrm{book}! \\ $$

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