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the-expression-ax-2-bx-c-is-divisible-by-x-1-has-reminder-2-when-divided-by-x-1-and-has-reminder-8-when-divided-by-x-2-find-the-value-of-a-b-and-c-




Question Number 9575 by j.masanja06@gmail.com last updated on 18/Dec/16
the expression ax^2  + bx + c is divisible  by x−1,has reminder 2 when divided by x+1,and has reminder 8 when divided by x−2.find the value of a,b and c.
theexpressionax2+bx+cisdivisiblebyx1,hasreminder2whendividedbyx+1,andhasreminder8whendividedbyx2.findthevalueofa,bandc.
Commented by ridwan balatif last updated on 18/Dec/16
P(x)≡ax^2 +bx+c  (x−1)is divisible P(x)→P(1)=0  a(1)^2 +b(1)+c=0  a+b+c=0...(1)  when P(x) is divided by (x+1), P(x) has reminder 2, it′s means P(−1)=2  a(−1)^2 +b(−1)+c=2  a−b+c=2...(2)  when P(x) is divided by (x−2), P(x) has reminder 8, it′s means P(2)=8  a(2)^2 +b(2)+c=8  4a+2b+c=8...(3)  (1)−(2)  a+b+c=0  a−b+c=2  −−−−−−(−)  2b=−2     b=−1...∗  (1)−(3)        a+b+c=0  4a+2b+c=8  −−−−−−−(−)           −3a−b=−8  −3a−(−1)=−8                   −3a=−7                          a=(7/3)...∗∗  a+b+c=0  (7/3)+(−1)+c=0  c=−(4/3)...∗∗∗  so, a=(7/3),b=−1,c=−(4/3)  P(x)≡(7/3)x^2 −x+(4/3)
P(x)ax2+bx+c(x1)isdivisibleP(x)P(1)=0a(1)2+b(1)+c=0a+b+c=0(1)whenP(x)isdividedby(x+1),P(x)hasreminder2,itsmeansP(1)=2a(1)2+b(1)+c=2ab+c=2(2)whenP(x)isdividedby(x2),P(x)hasreminder8,itsmeansP(2)=8a(2)2+b(2)+c=84a+2b+c=8(3)(1)(2)a+b+c=0ab+c=2()2b=2b=1(1)(3)a+b+c=04a+2b+c=8()3ab=83a(1)=83a=7a=73a+b+c=073+(1)+c=0c=43so,a=73,b=1,c=43P(x)73x2x+43

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