Question Number 4760 by malwaan last updated on 06/Mar/16
$${the}\:{number}\:\mathrm{27000001} \\ $$$${has}\:\mathrm{4}\:{prime}\:{factors}. \\ $$$${find}\:{thier}\:{sum} \\ $$
Commented by prakash jain last updated on 06/Mar/16
$$\mathrm{7},\mathrm{43},\mathrm{271},\mathrm{331} \\ $$$$\mathrm{7}+\mathrm{43}+\mathrm{271}+\mathrm{331}=\mathrm{652} \\ $$
Commented by prakash jain last updated on 06/Mar/16
$$\mathrm{27000000}+\mathrm{1}=\left(\mathrm{300}\right)^{\mathrm{3}} +\mathrm{1}^{\mathrm{3}} \\ $$$$\left(\mathrm{301}\right)\left(\mathrm{90000}−\mathrm{300}+\mathrm{1}\right)=\mathrm{301}×\mathrm{89701} \\ $$