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Question Number 4760 by malwaan last updated on 06/Mar/16
the number 27000001  has 4 prime factors.  find thier sum
$${the}\:{number}\:\mathrm{27000001} \\ $$$${has}\:\mathrm{4}\:{prime}\:{factors}. \\ $$$${find}\:{thier}\:{sum} \\ $$
Commented by prakash jain last updated on 06/Mar/16
7,43,271,331  7+43+271+331=652
$$\mathrm{7},\mathrm{43},\mathrm{271},\mathrm{331} \\ $$$$\mathrm{7}+\mathrm{43}+\mathrm{271}+\mathrm{331}=\mathrm{652} \\ $$
Commented by prakash jain last updated on 06/Mar/16
27000000+1=(300)^3 +1^3   (301)(90000−300+1)=301×89701
$$\mathrm{27000000}+\mathrm{1}=\left(\mathrm{300}\right)^{\mathrm{3}} +\mathrm{1}^{\mathrm{3}} \\ $$$$\left(\mathrm{301}\right)\left(\mathrm{90000}−\mathrm{300}+\mathrm{1}\right)=\mathrm{301}×\mathrm{89701} \\ $$

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