the-radii-of-curvatures-of-front-and-rear-surfaces-of-a-thin-convex-lens-are-30cm-and-12cm-respectively-what-is-its-focal-length-when-placed-inside-water-take-the-refractive-indices-of-glass-and-

FacebookTweetPin

Question Number 134319 by aurpeyz last updated on 02/Mar/21

$$theradiiofcurvaturesoffrontand$$$$rearsurfacesofathinconvexlens$$$$are30cmand12cmrespectively.$$$$whatisitsfocallengthwhenplaced$$$$insidewater?(taketherefractive$$$$indicesofglassandwatertobe1.52$$$$and1.33respectively$$

Commented by aurpeyz last updated on 02/Mar/21

$$plshelp$$

Answered by ajfour last updated on 02/Mar/21

$$\frac{1}{f}=(\frac{{\mu }_{glass}}{{\mu }_{water}}-1)(\frac{1}{R_1}-\frac{1}{R_2})$$$$=\left(\frac{1.52\times 3-4}{4}\right)(\frac{1}{30}+\frac{1}{12})$$$$\frac{1}{f}=\frac{0.14\times 7}{60}=\frac{0.98}{60}$$$$f=\frac{60}{0.98}\approx 60(1.02)=61.2cm$$

Commented by aurpeyz last updated on 02/Mar/21

$$okaysir.thanksalot$$

Commented by aurpeyz last updated on 02/Mar/21

$$(\frac{{\mu }_{glass}}{{\mu }_{water}}-1)=\frac{1.52-4}{4}??$$$$youhad\frac{1.52\times 3-4}{4}$$

Commented by aurpeyz last updated on 02/Mar/21

$$theoptionsare$$$$\left(a\right)141cm\left(b\right)-0.71cm\left(c\right)0.71cm$$$$\left(d\right)-141cm\left(e\right)14.1cm$$

Commented by ajfour last updated on 02/Mar/21

$$cantsay,myanswerseems$$$$correcttome!$$

Terms of Service
Privacy Policy
Contact: info@tinkutara.com

FacebookTweetPin