Question Number 6638 by Tawakalitu. last updated on 07/Jul/16
$${The}\:{radius}\:{of}\:{curvature}\:{of}\:{a}\:{thin}\:{equiconvex}\:{lens}\:{is}\:\mathrm{40}.\mathrm{0}\:{cm} \\ $$$${the}\:{lens}\:{is}\:{made}\:{of}\:{glass}\:{of}\:{refractive}\:{index}\:\mathrm{1}.\mathrm{660}.\:\:{find}\:{the}\: \\ $$$${position}\:{of}\:{the}\:{image}\:{of}\:{an}\:{object}\:{placed}\:{on}\:{the}\:{axis}\:{of}\:{the}\: \\ $$$${axis}\:{of}\:{the}\:{lens}\:{at}\:{a}\:{distance}\:{of}\:\mathrm{50}.\mathrm{0}\:{mm}\:\:{from}\:{the}\:{pole}. \\ $$$$ \\ $$