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The-side-of-a-square-is-measured-to-be-12cm-long-cofrect-to-the-nearest-cm-Find-the-maximum-absolute-error-and-the-maximum-percentage-error-for-a-The-length-of-the-square-Answer-0-5cm-




Question Number 71696 by TawaTawa last updated on 18/Oct/19
The side of a square is measured to be  12cm long cofrect  to the nearest  cm.  Find the maximum absolute error  and the maximum percentage error for  (a)    The length of the square     (Answer:  0.5cm,  4.17%)  (b)    The area of the square.      (Answer:    12.25cm,   8.5%)
Thesideofasquareismeasuredtobe12cmlongcofrecttothenearestcm.Findthemaximumabsoluteerrorandthemaximumpercentageerrorfor(a)Thelengthofthesquare(Answer:0.5cm,4.17%)(b)Theareaofthesquare.(Answer:12.25cm,8.5%)
Answered by MJS last updated on 19/Oct/19
“to the nearest cm” means ±.5cm because  you will round 11.5≈12.0 and 12.49^(.) ≈12.0  ⇒ absolute error of length is ±.5cm  ⇒ percentage is ((.5)/(12))≈4.17%  11.5≤x≤12.5 ⇔ 132.25≤x≤156.25  x=12±.5 ⇔ x^2 =144_(−11.75) ^(+12.25)   ⇒ absolute error of area is 12.25  ⇒ percentage is ((12.25)/(144))≈8.51%
tothenearestcmmeans±.5cmbecauseyouwillround11.512.0and12.49.12.0absoluteerroroflengthis±.5cmpercentageis.5124.17%11.5x12.5132.25x156.25x=12±.5x2=14411.75+12.25absoluteerrorofareais12.25percentageis12.251448.51%
Commented by TawaTawa last updated on 19/Oct/19
I  appreciate your time sir.  God bless you sir
Iappreciateyourtimesir.Godblessyousir

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