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The-sum-of-the-first-n-terms-of-a-series-is-given-by-S-n-n-2-7n-2-i-Find-a-formula-for-the-nth-term-ii-write-down-the-first-5-terms-of-the-sequence-




Question Number 76793 by necxxx last updated on 30/Dec/19
The sum of the first n terms of a series  is given by: S_n =n^2 +7n+2.  (i)Find a formula for the nth term  (ii)write down the first 5 terms of the  sequence
Thesumofthefirstntermsofaseriesisgivenby:Sn=n2+7n+2.(i)Findaformulaforthenthterm(ii)writedownthefirst5termsofthesequence
Commented by turbo msup by abdo last updated on 30/Dec/19
Σ_(k=0) ^(n−1)  S_k =Σ_(k=0) ^(n−1)  (k^2  +7k+2)  =Σ_(k=0) ^(n−1)  k^2  +7Σ_(k=0) ^(n−1)  k +2n  =(((n−1)(n−1+1)(2(n−1)+1))/6)  +7 (((n−1)n)/2) +2n  =((n(n−1)(2n−1))/6) +(7/2)n(n−1) +2n
k=0n1Sk=k=0n1(k2+7k+2)=k=0n1k2+7k=0n1k+2n=(n1)(n1+1)(2(n1)+1)6+7(n1)n2+2n=n(n1)(2n1)6+72n(n1)+2n
Commented by necxxx last updated on 01/Jan/20
thank you so so much.It′s clear now
thankyousosomuch.Itsclearnow
Answered by benjo 1/2 santuyy last updated on 30/Dec/19
(i) Un = Sn − Sn−1=  n^2  +7n+2 −(n−1)^2  −7(n−1)−2  =(2n−1)+7=2n + 6
(i)Un=SnSn1=n2+7n+2(n1)27(n1)2=(2n1)+7=2n+6
Answered by Kunal12588 last updated on 30/Dec/19
T_n =S_n −S_(n−1)   =n^2 −(n−1)^2 +7n−7(n−1)+2−2  =2n−1+7  =2n+6=2(n+3)  ∀ n>1  as for n=1   T_1 =S_1 =10       [not S_1 −S_0 ]
Tn=SnSn1=n2(n1)2+7n7(n1)+22=2n1+7=2n+6=2(n+3)n>1asforn=1T1=S1=10[notS1S0]
Commented by necxxx last updated on 01/Jan/20
Thank you
Thankyou

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