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The-two-side-of-rectangle-are-2x-and-5-2x-units-respectively-For-what-value-of-x-the-area-of-rectangle-will-be-maximum-




Question Number 134874 by bemath last updated on 08/Mar/21
The two side of rectangle are  2x and (!5−2x) units respectively  For what value of x the area of  rectangle will be maximum?
Thetwosideofrectangleare2xand(!52x)unitsrespectivelyForwhatvalueofxtheareaofrectanglewillbemaximum?
Commented by Ñï= last updated on 08/Mar/21
!5=5!(1−1!+(1/(2!))−(1/(3!))+(1/(4!))−(1/(5!)))=44  I got it.
!5=5!(11!+12!13!+14!15!)=44Igotit.
Answered by mr W last updated on 08/Mar/21
A=(2x)×(5−2x)≤((2x+(5−2x))/2)=(5/2)  max.=(5/2) when 2x=5−2x, i.e x=(5/4)
A=(2x)×(52x)2x+(52x)2=52max.=52when2x=52x,i.ex=54
Commented by bemath last updated on 08/Mar/21
this (!5−2x) sir ?
this(!52x)sir?
Commented by mr W last updated on 08/Mar/21
what do you want to say with !5? if  you mean !5=44, you can replace 5  with 44.
whatdoyouwanttosaywith!5?ifyoumean!5=44,youcanreplace5with44.
Commented by bemath last updated on 08/Mar/21
  in the book it says sir.  ha ha ha
in the book it says sir. ha ha ha
Commented by Ñï= last updated on 08/Mar/21
!5=5×6×7×8×9    ?
!5=5×6×7×8×9?
Commented by mr W last updated on 08/Mar/21

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