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the-velocities-of-air-particles-above-and-below-the-wing-of-an-aircraft-speeding-down-the-runway-at-a-given-instant-are-210m-s-and-200m-s-respectively-If-the-density-of-air-is-1-2kg-m-3-what-is-




Question Number 140869 by jlewis last updated on 13/May/21
the velocities of air particles   above and below the wing of an aircraft   speeding down the runway at a   given instant  are 210m/s and 200m/s   respectively.If the density of air is   1.2kg/m^3 ,what is the pressure   difference between the upper and  lower surface of the wing?
thevelocitiesofairparticlesaboveandbelowthewingofanaircraftspeedingdowntherunwayatagiveninstantare210m/sand200m/srespectively.Ifthedensityofairis1.2kg/m3,whatisthepressuredifferencebetweentheupperandlowersurfaceofthewing?
Answered by physicstutes last updated on 13/May/21
You might have come across the concept found in Benouli′s equation  P + (1/2)ρv^2  = constant.  which tells us that the relationship between pressure, density and speed is  P = (1/2)ρv^2   so P_(above)  = (1/2)ρv_(above) ^2  = (1/2)(1.2)(210)^2  = 26,460 Pa    P_(below)  = (1/2)ρv_(below) ^2  = (1/2)(1.2)(200)^2  = 24,000 Pa  pressure difference = ΔP = P_(above) −P_(below)  = 26,460 − 24000= 2,460 Pa
YoumighthavecomeacrosstheconceptfoundinBenoulisequationP+12ρv2=constant.whichtellsusthattherelationshipbetweenpressure,densityandspeedisP=12ρv2soPabove=12ρvabove2=12(1.2)(210)2=26,460PaPbelow=12ρvbelow2=12(1.2)(200)2=24,000Papressuredifference=ΔP=PabovePbelow=26,46024000=2,460Pa
Commented by jlewis last updated on 13/May/21
thankz alot
thankzalot

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