Three-interior-angles-of-a-nonagon-are-equal-and-the-sum-of-the-other-six-is-1050-Find-the-size-of-one-of-the-equal-angles-

Question Number 71533 by pete last updated on 16/Oct/19

$$\mathrm{Three}\:\mathrm{interior}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{a}\:\mathrm{nonagon}\:\mathrm{are} \\ $$$$\mathrm{equal}\:\mathrm{and}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{other}\:\mathrm{six}\:\mathrm{is}\:\mathrm{1050}° \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{size}\:\mathrm{of}\:\mathrm{one}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equal}\:\mathrm{angles}. \\ $$

Answered by MJS last updated on 17/Oct/19

$$\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{interior}\:\mathrm{angles}\:\mathrm{is}\:\mathrm{1260}° \\ $$$$\frac{\mathrm{1260}°−\mathrm{1050}°}{\mathrm{3}}=\mathrm{70}° \\ $$

Commented by pete last updated on 18/Oct/19

$$\mathrm{Thanks}\:\mathrm{very}\:\mathrm{much}\:\mathrm{sir} \\ $$

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