Three-school-children-share-some-oranges-as-follows-Akwasi-gets-1-3-of-the-total-and-the-remainder-is-shared-between-Abena-and-Juana-in-the-ratio-2-3-If-Abena-gets-24-oranges-how-many-does-Ak

Question Number 67108 by otchereabdullai@gmail.com last updated on 22/Aug/19

Three school children share some

oranges as follows : Akwasi gets \frac{1}{3} of

the total and the remainder is shared

between Abena and Juana in the ratio

2 : 3 . If Abena gets 24 oranges, how

many does Akwasi get .

Commented by Prithwish sen last updated on 23/Aug/19

Akwasi gets = (24 \times \frac{5}{2}) \times \frac{1}{2} = 30

Commented by otchereabdullai@gmail.com last updated on 23/Aug/19

thank you sir

Answered by Rasheed.Sindhi last updated on 23/Aug/19

N u m b e r o f o r a n g e s : n

A k w s s i g e t s \frac{n}{3}

R e m a i n i n g : n - \frac{n}{3} = \frac{2 n}{3}

A b e n a g e t s \frac{\frac{2 n}{3}}{5} \times 2, w h i c h i s e q u a l t o 24

\frac{\frac{2 n}{3}}{5} \times 2 = 24

\frac{2 n}{3} = 24 \times \frac{5}{2} = 60

\frac{n}{3} = \frac{60}{2} = 30

A k w a s i g e t s 30 o r a n g e s .

Commented by otchereabdullai@gmail.com last updated on 23/Aug/19

thank you sir

Answered by Rasheed.Sindhi last updated on 23/Aug/19

N u m b e r o f o r a n g e s : x

(\begin{matrix} A k w s i & A b e n a & J u a n a \\ R e m a i n i n g \times (2 / 5) & R e m a i n i n g \times (3 / 5 \\ x / 3 & (2 x / 3) \times (2 / 5) = 24 & (2 x / 3) \times (3 / 5) \end{matrix})

(2 x / 3) \times (2 / 5) = 24

x / 3 = \frac{24 \times (5 / 2)}{2} = \frac{60}{2} = 30

A k w a s i g e t s 30 o r a n g e s .

Commented by otchereabdullai@gmail.com last updated on 23/Aug/19

thank you sir