Question Number 67108 by otchereabdullai@gmail.com last updated on 22/Aug/19
$$\mathrm{Three}\:\mathrm{school}\:\mathrm{children}\:\mathrm{share}\:\mathrm{some}\: \\ $$$$\mathrm{oranges}\:\mathrm{as}\:\mathrm{follows}:\:\mathrm{Akwasi}\:\mathrm{gets}\:\frac{\mathrm{1}}{\mathrm{3}}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{total}\:\mathrm{and}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{is}\:\mathrm{shared} \\ $$$$\mathrm{between}\:\mathrm{Abena}\:\mathrm{and}\:\mathrm{Juana}\:\mathrm{in}\:\mathrm{the}\:\mathrm{ratio} \\ $$$$\mathrm{2}:\:\mathrm{3}\:.\:\mathrm{If}\:\mathrm{Abena}\:\mathrm{gets}\:\mathrm{24}\:\mathrm{oranges}\:,\:\mathrm{how} \\ $$$$\mathrm{many}\:\mathrm{does}\:\mathrm{Akwasi}\:\mathrm{get}. \\ $$
Commented by Prithwish sen last updated on 23/Aug/19
$$\mathrm{Akwasi}\:\mathrm{gets}\:=\left(\:\mathrm{24}×\frac{\mathrm{5}}{\mathrm{2}}\right)×\frac{\mathrm{1}}{\mathrm{2}}\:\:=\:\mathrm{30}\: \\ $$
Commented by otchereabdullai@gmail.com last updated on 23/Aug/19
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$
Answered by Rasheed.Sindhi last updated on 23/Aug/19
$${Number}\:{of}\:{oranges}:\:{n} \\ $$$${Akwssi}\:{gets}\:\frac{{n}}{\mathrm{3}} \\ $$$${Remaining}:{n}−\:\frac{{n}}{\mathrm{3}}=\frac{\mathrm{2}{n}}{\mathrm{3}} \\ $$$${Abena}\:{gets}\:\frac{\frac{\mathrm{2}{n}}{\mathrm{3}}}{\mathrm{5}}×\mathrm{2},{which}\:{is}\:{equal}\:{to}\:\mathrm{24} \\ $$$$\:\:\:\:\:\:\:\frac{\frac{\mathrm{2}{n}}{\mathrm{3}}}{\mathrm{5}}×\mathrm{2}=\mathrm{24} \\ $$$$\:\:\:\:\frac{\mathrm{2}{n}}{\mathrm{3}}=\mathrm{24}×\frac{\mathrm{5}}{\mathrm{2}}=\mathrm{60} \\ $$$$\:\:\:\:\:\frac{{n}}{\mathrm{3}}=\frac{\mathrm{60}}{\mathrm{2}}=\mathrm{30} \\ $$$${Akwasi}\:{gets}\:\mathrm{30}\:{oranges}. \\ $$
Commented by otchereabdullai@gmail.com last updated on 23/Aug/19
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$
Answered by Rasheed.Sindhi last updated on 23/Aug/19
$${Number}\:{of}\:\:{oranges}:\:{x} \\ $$$$\begin{pmatrix}{{Akwsi}}&{\:\:\:\:\:\:\:\:\:\:\:\:\:{Abena}}&{\:\:\:\:\:\:\:\:{Juana}}\\{}&{\mathcal{R}{emaining}×\left(\mathrm{2}/\mathrm{5}\right)}&{\mathcal{R}{emaining}×\left(\mathrm{3}/\mathrm{5}\right.}\\{\:\:\:{x}/\mathrm{3}}&{\:\left(\mathrm{2}{x}/\mathrm{3}\right)×\left(\mathrm{2}/\mathrm{5}\right)=\mathrm{24}}&{\:\:\:\:\:\left(\mathrm{2}{x}/\mathrm{3}\right)×\left(\mathrm{3}/\mathrm{5}\right)}\end{pmatrix}\: \\ $$$$ \\ $$$$\left(\mathrm{2}{x}/\mathrm{3}\right)×\left(\mathrm{2}/\mathrm{5}\right)=\mathrm{24} \\ $$$${x}/\mathrm{3}=\frac{\mathrm{24}×\left(\mathrm{5}/\mathrm{2}\right)}{\mathrm{2}}=\frac{\mathrm{60}}{\mathrm{2}}=\mathrm{30} \\ $$$${Akwasi}\:{gets}\:\mathrm{30}\:{oranges}. \\ $$
Commented by otchereabdullai@gmail.com last updated on 23/Aug/19
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$