Question Number 139742 by mathocean1 last updated on 30/Apr/21
$${Today}\:{is}\:{the}\:{birthday}\:{of}\:{Matongue}. \\ $$$${His}\:{age}\:{is}\:{the}\:{double}\:{of}\:{his}\:{daughter}'{s} \\ $$$${age}.\:{Will}\:{this}\:{event}\:{happen}\:{in}\:{the} \\ $$$${futur}? \\ $$$${a}.{Yes}\:{Each}\:{two}\:{years} \\ $$$${b}.\:{Yes}\:{In}\:{two}\:{years}. \\ $$$${c}.\:{No} \\ $$$${d}.\:{Any}\:{correct}\:{answer}. \\ $$
Answered by Rasheed.Sindhi last updated on 01/May/21
$${d}:\:{age}\:{of}\:{dauvhter}\:{today}. \\ $$$$\mathrm{2}{d}:\:{age}\:{of}\:{Matongue}\:{today}. \\ $$$${Let}\:{after}\:{n}\:{years}\:{the}\:{age}\:{of}\:{Matongue} \\ $$$${will}\:{be}\:{double}\:{of}\:{his}\:{daughter}\: \\ $$$$\boldsymbol{{again}}. \\ $$$$\mathrm{2}{d}+{n}=\mathrm{2}\left({d}+{n}\right) \\ $$$${n}=\mathrm{2}{n} \\ $$$${n}=\mathrm{0} \\ $$$${The}\:{event}\:{never}\:{will}\:{come}\:{again}. \\ $$$$\left({c}\right)\:{is}\:{correct}. \\ $$