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ty-y-ty-0-y-0-1-

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Question Number 141243 by Ar Brandon last updated on 16/May/21
{ ((ty′′+y′+ty=0)),((y(0^+ )=1)) :}
$$\begin{cases}{\mathrm{ty}''+\mathrm{y}'+\mathrm{ty}=\mathrm{0}}\\{\mathrm{y}\left(\mathrm{0}^{+} \right)=\mathrm{1}}\end{cases} \\ $$

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