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u-1-1-u-n-1-n-2-n-1-n-2-n-R-lim-n-u-n-




Question Number 138571 by bemath last updated on 15/Apr/21
 { ((u_1 =1)),((u_(n+1) = ((n^2 −n+1)/n^2 ))) :} ; ∀n∈R   lim_(n→∞)  u_n  =?
{u1=1un+1=n2n+1n2;nRlimnun=?
Answered by mathmax by abdo last updated on 15/Apr/21
⇒u_n =(((n−1)^2 −(n−1)+1)/((n−1)^2 )) =((n^2 −2n+1−n+2)/(n^2 −2n+1)) =((n^2 −3n+3)/(n^2 −2n+1))  ⇒lim_(n→+∞)  u_n =lim_(n→+∞) (n^2 /n^2 )=1
un=(n1)2(n1)+1(n1)2=n22n+1n+2n22n+1=n23n+3n22n+1limn+un=limn+n2n2=1

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