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u-R-2-R-u-x-x-2-y-2-2xu-0-




Question Number 293 by 123456 last updated on 25/Jan/15
u:R^2 →R  (∂u/∂x)(x^2 +y^2 )+2xu=0
u:R2Rux(x2+y2)+2xu=0
Answered by prakash jain last updated on 19/Dec/14
(du/u)=((2xdx)/(x^2 +y^2 ))  x^2 +y^2 =t⇒2xdx=dt  ln u=ln t+C=ln (x^2 +y^2 )+C  u=(x^2 +y^2 )∙C_1
duu=2xdxx2+y2x2+y2=t2xdx=dtlnu=lnt+C=ln(x2+y2)+Cu=(x2+y2)C1