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Question Number 13005 by 1630321995 last updated on 10/May/17
using De Moivre theorem solve the equation (x+1)^5 +(x−1)^5 =0
usingDeMoivretheoremsolvetheequation(x+1)5+(x1)5=0
Answered by mrW1 last updated on 10/May/17
(x+1)^5 −(1−x)^5 =0  (x+1)^5 =(1−x)^5   x+1=1−x  2x=0  ⇒x=0
(x+1)5(1x)5=0(x+1)5=(1x)5x+1=1x2x=0x=0

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