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Question Number 66355 by gunawan last updated on 13/Aug/19
Value of x satiesfied y=((log_4 (x^2 −1))/(4x^2 +2x+1))  negative value is...  a. −1<x<(√2)  b. −(√2)<x<1  c. −(√2)<x<(√2)  d. −(√2)<x<−1  e. x<−2
Valueofxsatiesfiedy=log4(x21)4x2+2x+1negativevalueisa.1<x<2b.2<x<1c.2<x<2d.2<x<1e.x<2
Commented by kaivan.ahmadi last updated on 13/Aug/19
x^2 −1>0⇒x>1 or x<−1  4x^2 +2x+1>0⇒x∈R  ⇒D_y =x>1 or x<0  y<0⇒log_4 (x^2 −1)<0⇒x^2 −1<1⇒x^2 <2⇒−(√2)<x<(√2)  so the answer is  −(√2)<x<−1 and 1<x<(√2)
x21>0x>1orx<14x2+2x+1>0xRDy=x>1orx<0y<0log4(x21)<0x21<1x2<22<x<2sotheansweris2<x<1and1<x<2

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