Question Number 76726 by Rio Michael last updated on 29/Dec/19
$$\:\mathrm{var}\left(\mathrm{x}\right)\:=\:\mathrm{2}\:\mathrm{then}\:\mathrm{var}\left(\mathrm{2x}\:−\mathrm{3}\right)=? \\ $$$$\mathrm{E}\left(\mathrm{x}\right)\:=\:\mathrm{2}\:\mathrm{then}\:\mathrm{E}\left(\mathrm{2x}\:−\mathrm{3}\right)\:=\:? \\ $$
Answered by john santu last updated on 30/Dec/19
$${E}\left({x}\right)=\underset{{x}} {\sum}{xf}\left({x}\right)=\mathrm{2}\: \\ $$$${so}\:{E}\left(\mathrm{2}{x}−\mathrm{3}\right)\:=\:\underset{{x}} {\sum}\left(\mathrm{2}{x}−\mathrm{3}\right){f}\left({x}\right) \\ $$$$=\:\mathrm{2}\underset{{x}} {\sum}{xf}\left({x}\right)−\underset{{x}} {\sum}\mathrm{3}{f}\left({x}\right) \\ $$$$=\:\mathrm{4}−\mathrm{3}\underset{{x}} {\sum}{f}\left({x}\right) \\ $$
Commented by john santu last updated on 30/Dec/19
$${note}\::\:\underset{{x}} {\sum}{f}\left({x}\right)=\mathrm{1} \\ $$
Answered by benjo 1/2 santuyy last updated on 30/Dec/19
$${using}\:{by}\:{theorem}\: \\ $$$${E}\left(\mathrm{2}{x}−\mathrm{3}\right)=\mathrm{2}{E}\left({x}\right)−\mathrm{3}\: \\ $$$${so}\:{we}\:{get}\:{E}\left(\mathrm{2}{x}−\mathrm{3}\right)=\mathrm{2}×\mathrm{2}−\mathrm{3}=\mathrm{1} \\ $$
Answered by benjo 1/2 santuyy last updated on 30/Dec/19
$${var}\left(\mathrm{2}{x}−\mathrm{3}\right)=\mathrm{2}^{\mathrm{2}} {var}\left({x}\right)\:=\:\mathrm{4}×\mathrm{2}\:=\mathrm{8} \\ $$
Commented by Rio Michael last updated on 30/Dec/19
$$\mathrm{thanks}\:\mathrm{guys} \\ $$
Commented by john santu last updated on 30/Dec/19
$${your}\:{welcome}\:{bro} \\ $$