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Question Number 3950 by Rasheed Soomro last updated on 25/Dec/15

W e c a n m a k e a c y l l i n d e r f r o m a

r e c t a n g l e b y c o n n e c t i n g i t s o p p o s i t e

e d g e s .

S u p p o s e w e h a v e t w o c o p i e s o f a

n o n - s q u a r e r e c t a n g l e . F r o m

o n e c o p y w e m a k e a l o n g c y l l i n d e r

b y c o n n e c t i n g l o n g e d g e s o f i t

w h e r e a s f r o m o t h e r c o p y b y c o n n e c t i n g

s h o r t e d g e s a s h o r t c y l l i n d e r i s m a d e .

C o m p a r e t h e v o l u m e s o f t h e s e t w o

c y l l i n d e r s .

Answered by prakash jain last updated on 25/Dec/15

a = l e n g t h, b w i d t h

c a s e i : r a d i u s = \frac{a}{2 π}, volume = π \frac{a^{2}}{4 π^{2}} b = \frac{a^{2} b}{4 π}

c a s e i i : r a d i u s = \frac{b}{2 π}, volume = π \frac{b^{2}}{4 π^{2}} a = \frac{b^{2} a}{4 π}

r a t i o = \frac{a}{b}

Commented by Rasheed Soomro last updated on 25/Dec/15

T h α n k S!

I t m e a n s c y l l i n d e r o f g r e a t e r h e i g h t h a s

s m a l l v o l u m e .

\frac{C y l l i n d e r o f h e i g h t b}{C y l l i n d e r o f h e i g h t a} = \frac{a}{b}