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Question Number 7222 by Tawakalitu. last updated on 16/Aug/16
What are the possible solution satisfying  x^y  = y^x
Whatarethepossiblesolutionsatisfyingxy=yx
Commented by Tawakalitu. last updated on 17/Aug/16
I appreciate your effort. thanks sir.
Iappreciateyoureffort.thankssir.
Commented by Yozzia last updated on 17/Aug/16
x=y∈C constitutes part of the solution  set.  −−−−−−−−−−−−−−−−−−−−−−−  x^y =y^x   ylnx=xlny  −(1/x)lnx=−(1/y)lny  x^(−1) lnx^(−1) =y^(−1) lny^(−1)   e^(lnx^(−1) ) lnx^(−1) =e^(lny^(−1) ) lny^(−1)   W(e^(lnx^(−1) ) lnx^(−1) )=W(e^(lny^(−1) ) lny^(−1) )  ⇒lnx^(−1) =lny^(−1)   ⇒(1/x)=(1/y)⇒x=y∈C.  By this working, x^y =y^x  ⇔x=y.
x=yCconstitutespartofthesolutionset.xy=yxylnx=xlny1xlnx=1ylnyx1lnx1=y1lny1elnx1lnx1=elny1lny1W(elnx1lnx1)=W(elny1lny1)lnx1=lny11x=1yx=yC.Bythisworking,xy=yxx=y.

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