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what-are-the-solutions-of-3x-2-1-n-where-n-N-




Question Number 73308 by wo1lxjwjdb last updated on 10/Nov/19
what are the solutions  of (√(3x^2 +1))=n where n∈N
whatarethesolutionsof3x2+1=nwherenN
Commented by MJS last updated on 10/Nov/19
n_k =(1/2)((2−(√3))^k +(2+(√3))^k )=cosh (kln (2−(√3)))  x_k =−((√3)/3)sinh (kln (2−(√3)))  k, n_k , x_k  ∈N
nk=12((23)k+(2+3)k)=cosh(kln(23))xk=33sinh(kln(23))k,nk,xkN
Commented by MJS last updated on 10/Nov/19
you mean n∈N
youmeannN
Commented by kaivan.ahmadi last updated on 10/Nov/19
n∈N  3x^2 +1=n^2 ⇒3x^2 =n^2 −1⇒x^2 =((n^2 −1)/3)⇒  x=(√((n^2 −1)/3))
nN3x2+1=n23x2=n21x2=n213x=n213
Commented by wo1lxjwjdb last updated on 10/Nov/19
when is it a whole number?
whenisitawholenumber?
Commented by MJS last updated on 10/Nov/19
n∈N  x∈?  if x∈R  x=±(√((n^2 −1)/3)); n>0       [for x∈C we also get n=0; x=((√3)/3)i]  if x∈N  same equation, solutions are:  x∈{0, 1, 4, 15, 56, 209, 780, ...}  n∈{1, 2, 7, 26, 97, 362, 1351, ...}
nNx?ifxRx=±n213;n>0[forxCwealsogetn=0;x=33i]ifxNsameequation,solutionsare:x{0,1,4,15,56,209,780,}n{1,2,7,26,97,362,1351,}
Commented by kaivan.ahmadi last updated on 10/Nov/19
Mr MJS answered this quoestion.
MrMJSansweredthisquoestion.

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