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Question Number 137473 by mr W last updated on 03/Apr/21
what is larger? 99^(100)  or 100^(99) ?
whatislarger?99100or10099?
Answered by MJS_new last updated on 03/Apr/21
n^(n+1) >(n+1)^n  ∀ n≥3
nn+1>(n+1)nn3
Commented by mr W last updated on 03/Apr/21
yes sir.
yessir.
Answered by mr W last updated on 03/Apr/21
f(x)=x^(1/x) =e^((ln x)/x)   f′(x)=x^(1/x) ((1/x^2 )−((ln x)/x^2 ))=(1−ln x)x^((1/x)−2)   for x<e: f′(x)>0 ⇒f(x) is strictly increasing  for x>e: f′(x)<0 ⇒f(x) is strictly decreasing  that means for 3≤m<n:  m^(1/m) >n^(1/n)   ⇒(m^(1/m) )^(mn) >(n^(1/n) )^(mn)   ⇒m^n >n^m   so 99^(100) >100^(99)
f(x)=x1x=elnxxf(x)=x1x(1x2lnxx2)=(1lnx)x1x2forx<e:f(x)>0f(x)isstrictlyincreasingforx>e:f(x)<0f(x)isstrictlydecreasingthatmeansfor3m<n:m1m>n1n(m1m)mn>(n1n)mnmn>nmso99100>10099

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