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Question Number 77574 by jagoll last updated on 08/Jan/20
what is maximum   value of y= (3x+4)^2 ×sin (2x)
whatismaximumvalueofy=(3x+4)2×sin(2x)
Commented by MJS last updated on 08/Jan/20
sin 2x =−1 ⇒ x=nπ−(π/4)=((4n−1)/4)π  sin 2x =+1 ⇒ x=nπ+(π/4)=((4n+1)/4)π  n∈Z    f(x)=(3x+4)^2 sin 2x  f(((4n−1)/4)π)=−(((12πn−3π+16)^2 )/(16))  n=±10^3  ⇒ f(x)≈−8.9×10^7   n=±10^6  ⇒ f(x)≈−8.9×10^(13)   n=±10^9  ⇒ f(x)≈−8.9×10^(19)   ...
sin2x=1x=nππ4=4n14πsin2x=+1x=nπ+π4=4n+14πnZf(x)=(3x+4)2sin2xf(4n14π)=(12πn3π+16)216n=±103f(x)8.9×107n=±106f(x)8.9×1013n=±109f(x)8.9×1019
Commented by jagoll last updated on 08/Jan/20
please
please
Commented by MJS last updated on 08/Jan/20
no maximum because lim_(x→±∞)  (3x+4)^2  =+∞
nomaximumbecauselimx±(3x+4)2=+
Commented by jagoll last updated on 08/Jan/20
if minimum sir?
ifminimumsir?
Commented by MJS last updated on 08/Jan/20
also no minimum  −1≤sin 2x ≤1  −∞<(3x+4)^2 sin 2x<+∞
alsonominimum1sin2x1<(3x+4)2sin2x<+
Commented by jagoll last updated on 08/Jan/20
thanks you sir
thanksyousir
Commented by jagoll last updated on 08/Jan/20
sir minimum (3x+4)^2  = 0   why minimum (3x+4)^2 ×sin (2x) = −∞
sirminimum(3x+4)2=0whyminimum(3x+4)2×sin(2x)=
Commented by MJS last updated on 08/Jan/20
...similar for  f(((4n+1)/4)π)=(((12πn+3π+16)^2 )/(16))
similarforf(4n+14π)=(12πn+3π+16)216
Commented by jagoll last updated on 08/Jan/20
thanks you sir
thanksyousir

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