Question Number 8217 by tawakalitu last updated on 02/Oct/16

Commented by 123456 last updated on 04/Oct/16

Commented by sandy_suhendra last updated on 04/Oct/16

Commented by 123456 last updated on 04/Oct/16

Commented by sandy_suhendra last updated on 04/Oct/16

Commented by tawakalitu last updated on 04/Oct/16

Answered by sandy_suhendra last updated on 03/Oct/16
![[(1+x+x^2 )+x^3 (1+x+x^2 )]^6 =[(x^3 +1)(x^2 +x+1)]^6 =(x^3 +1)^6 (x^2 +x+1)^6 (x^3 +1)^6 =(x^3 )^6 +6(x^3 )^5 +...+6x^3 +1 [x^2 +(x+1)]^6 =1(x^2 )^6 +6(x^2 )^5 (x+1)+...+6x^2 (x+1)^5 +1(x+1)^6 6x^2 (x+1)^5 =6x^2 (x^5 +5x^4 +...+5x+1)⇒30x^3 (x+1)^6 =x^6 +6x^5 +...+20x^3 +...+1 the term of x^3 comes from ⇒ 6x^3 +30x^3 +20x^3 =56x^3 so the coefficient of x^3 is 56](https://www.tinkutara.com/question/Q8235.png)
Commented by tawakalitu last updated on 03/Oct/16
